Web development Lab

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3)  Create Web pages using AJAX.

 

SOURCE CODE:-

<?php

// Array with names

$a[] = "Anna";

$a[] = "Brittany";

$a[] = "Cinderella";

$a[] = "Diana";

$a[] = "Eva";

$a[] = "Fiona";

$a[] = "Gunda";

$a[] = "Hege";

$a[] = "Inga";

$a[] = "Johanna";

$a[] = "Kitty";

$a[] = "Linda";

$a[] = "Nina";

$a[] = "Ophelia";

$a[] = "Petunia";

$a[] = "Amanda";

$a[] = "Raquel";

$a[] = "Cindy";

$a[] = "Doris";

$a[] = "Eve";

$a[] = "Evita";

$a[] = "Sunniva";

$a[] = "Tove";

$a[] = "Unni";

$a[] = "Violet";

$a[] = "Liza";

$a[] = "Elizabeth";

$a[] = "Ellen";

$a[] = "Wenche";

$a[] = "Vicky";

// get the q parameter from URL

$q = $_REQUEST["q"];

 

$hint = "";

// lookup all hints from array if $q is different from "" if ($q !== "") {

$q = strtolower($q);

$len=strlen($q);

foreach($a as $name) {

if (stristr($q, substr($name, 0, $len))) { if ($hint === "") {

$hint = $name;

} else {

$hint .= ", $name";

}

}

}

}

// Output "no suggestion" if no hint was found or output correct values echo $hint === "" ? "no suggestion" : $hint;

?>

Hint.html

<html>

<head>

<script>

function showHint(str) { if (str.length == 0) {

document.getElementById("txtHint").innerHTML = ""; return;

} else {

var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() {

if (this.readyState == 4 && this.status == 200) {

document.getElementById("txtHint").innerHTML = this.responseText;

}

};

xmlhttp.open("GET", "gethint.php?q=" + str+"", true); xmlhttp.send();

}

}

</script>

</head>

<body>

 

<p><b>Start typing a name in the input field below:</b></p>

<form>

First name: <input type="text" onkeyup="showHint(this.value)">

</form>

<p>Suggestions: <span id="txtHint"></span></p>

</body>

</html>

 

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